python 連続した数のカウント方法

s = input()
cnt00 = 0
i = 0
while i + 1 < len(s):
    if s[i] == "0" and s[i+1] == "0":
        cnt00 += 1
        i += 1
    i += 1

print(len(s) - cnt00)

def min_keypresses(S):
    num_presses = 0

    while S > 0:
        if S % 100 == 0:
            S //= 100
        else:
            S //= 10
            
        num_presses += 1

    return num_presses

print(min_keypresses(40004)) # 4
print(min_keypresses(1355506027)) # 10
print(min_keypresses(10888869450418352160768000001)) # 27

import re

#S = input()
S = '1002002'
res = re.findall(r'00|\d', S)
print(res)  # ['1', '00', '2', '00', '2']
print(len(res))  # 5

s = "1002002"
# len = 7
s_len = len(s)

ss = s.replace('00', '')
# len = 3
ss_len = len(ss)

#  (7 - 3) / 2 = 2 
ans = (int(s_len) - int(ss_len)) // 2
print(ans)