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pythonで、CPPのヘッダ部分をかき集めてCSVに書く!

Posted at

こんな感じでパス設定すればOK

#! /usr/bin/env python
# -*- coding: utf-8 -*-

import glob
import csv

if __name__ == '__main__':


    filelist=[]
    filelist.extend(glob.glob('./src/**/*.cpp', recursive=True))
    filelist.extend(glob.glob('./src/**/*.c', recursive=True))
    filelist.extend(glob.glob('./inc/**/*.hpp', recursive=True))
    filelist.extend(glob.glob('./inc/**/*.h', recursive=True))

    header_list=[]
    header_list.append(["src","line","include"])

    for filepath in filelist:
        print(filepath)
        with open(filepath, encoding='utf-8') as f:
            for i, line in enumerate(f):
                if '#include' in line:
                    line = line.replace('\n','')
                    header_list.append([filepath,str(i),line])


    with open('./sample_writer.csv', 'w') as f:
        writer = csv.writer(f)
        writer.writerows(header_list)
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