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perlワンライナーで正規表現を使って欲しいとこだけ抜き出す

Last updated at Posted at 2018-08-02

例えばこんな感じのVagrantfileからフォワードしているhost側のポートを抜き出したいとする

$ cat Vagrantfile
Vagrant.configure(2) do |config|
  config.vm.box = "centos/7"
  config.vm.hostname = "centos7"
  config.vm.network "forwarded_port", host: 8080, guest: 80, host_ip: "127.0.0.1"
  config.vm.network "forwarded_port", host: 18080, guest: 18080, host_ip: "127.0.0.1"
  config.vm.network "forwarded_port", host: 10443, guest: 443, host_ip: "127.0.0.1"
  config.vm.network "private_network", ip: "192.168.33.12"
  config.vm.synced_folder ".", "/vagrant", type: "virtualbox", mount_options: ['dmode=777','fmode=744']
  config.vm.provider "virtualbox" do |vb|
    vb.name = "centos7"
    vb.cpus = 2
    vb.memory = 2048
  end
end

抜き出し

$ cat Vagrantfile | perl -nle 'print $1 if /host: (\d+)/'
8080
18080
10443

行ごと表示したければprintの後の$1を消すだけで良い

$ cat Vagrantfile | perl -nle 'print if /host: (\d+)/'
  config.vm.network "forwarded_port", host: 8080, guest: 80, host_ip: "127.0.0.1"
  config.vm.network "forwarded_port", host: 18080, guest: 18080, host_ip: "127.0.0.1"
  config.vm.network "forwarded_port", host: 10443, guest: 443, host_ip: "127.0.0.1"
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