【Swift2】iOSの端末モデル名を取得する

目的

iOSアプリで利用している端末のモデル名(「iPhone 5S」とか「iPad Air」とか)を取得したい。

基本的には【Swift】使っている端末の情報を取得の情報で良いのだが、Swift2だと微妙に修正しないと動かなかったので修正後のコードを記載する。
ついでにiPhone6S PlusやiPad Proなんかのマッピングも追記。

実装

UIDeviceクラスを拡張してあげる方向。

UIDevice+platform.swift

// cf. http://www.enterpriseios.com/wiki/iOS_Devices
private let DeviceList = [
    /* iPod Touch 5 */    "iPod5,1": "iPod Touch 5",
    /* iPod Touch 6 */    "iPod7,1": "iPod Touch 6",
    /* iPhone 4 */        "iPhone3,1": "iPhone 4", "iPhone3,2": "iPhone 4", "iPhone3,3": "iPhone 4",
    /* iPhone 4S */       "iPhone4,1": "iPhone 4S",
    /* iPhone 5 */        "iPhone5,1": "iPhone 5", "iPhone5,2": "iPhone 5",
    /* iPhone 5C */       "iPhone5,3": "iPhone 5C", "iPhone5,4": "iPhone 5C",
    /* iPhone 5S */       "iPhone6,1": "iPhone 5S", "iPhone6,2": "iPhone 5S",
    /* iPhone 6 */        "iPhone7,2": "iPhone 6",
    /* iPhone 6 Plus */   "iPhone7,1": "iPhone 6 Plus",
    /* iPhone 6S */       "iPhone8,1": "iPhone 6S",
    /* iPhone 6S Plus */  "iPhone8,2": "iPhone 6S Plus",
    /* iPad 2 */          "iPad2,1": "iPad 2", "iPad2,2": "iPad 2", "iPad2,3": "iPad 2", "iPad2,4": "iPad 2",
    /* iPad 3 */          "iPad3,1": "iPad 3", "iPad3,2": "iPad 3", "iPad3,3": "iPad 3",
    /* iPad 4 */          "iPad3,4": "iPad 4", "iPad3,5": "iPad 4", "iPad3,6": "iPad 4",
    /* iPad Air */        "iPad4,1": "iPad Air", "iPad4,2": "iPad Air", "iPad4,3": "iPad Air",
    /* iPad Air 2 */      "iPad5,3": "iPad Air 2", "iPad5,4": "iPad Air 2",
    /* iPad Mini */       "iPad2,5": "iPad Mini", "iPad2,6": "iPad Mini", "iPad2,7": "iPad Mini",
    /* iPad Mini 2 */     "iPad4,4": "iPad Mini 2", "iPad4,5": "iPad Mini 2", "iPad4,6": "iPad Mini 2",
    /* iPad Mini 3 */     "iPad4,7": "iPad Mini 3", "iPad4,8": "iPad Mini 3", "iPad4,9": "iPad Mini 3",
    /* iPad Mini 4 */     "iPad5,1": "iPad Mini 4", "iPad5,2": "iPad Mini 4",
    /* iPad Pro */        "iPad6,7": "iPad Pro", "iPad6,8": "iPad Pro",
    /* Simulator */       "x86_64": "Simulator", "i386": "Simulator",    
]

extension UIDevice {

    var platform: String {
        var systemInfo = utsname()
        uname(&systemInfo)

        let mirror = Mirror(reflecting: systemInfo.machine)
        var identifier = ""

        for child in mirror.children {
            if let value = child.value as? Int8 where value != 0 {
                identifier.append(UnicodeScalar(UInt8(value)))
            }
        }
        return identifier
    }

    var modelName: String {
        let identifier = platform
        return DeviceList[identifier] ?? identifier
    }
}

使い方

let device = UIDevice.currentDevice()
print(device.platform) // iPhone8,2
print(device.modelName) // iPhone 6S Plus

参考

【Swift】使っている端末の情報を取得 - Qiita
http://qiita.com/ryokosuge/items/9d954f54ffc6692c89c4

iOS Devices | Enterprise iOS
http://www.enterpriseios.com/wiki/iOS_Devices