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自分用: tscのtarget optionで排出されるClass形式纏め

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はじめに

npmパッケージで提供されたes6形式のclassをextendsした際にハマったのでこの辺を整理してみようと思う

ソースファイル

class Base {
}

class SubClass extends Base {
}

target es6 && esnext && es2018

class Base {
}
class SubClass extends Base {
}

target es5

var __extends = (this && this.__extends) || (function () {
    var extendStatics = Object.setPrototypeOf ||
        ({ __proto__: [] } instanceof Array && function (d, b) { d.__proto__ = b; }) ||
        function (d, b) { for (var p in b) if (b.hasOwnProperty(p)) d[p] = b[p]; };
    return function (d, b) {
        extendStatics(d, b);
        function __() { this.constructor = d; }
        d.prototype = b === null ? Object.create(b) : (__.prototype = b.prototype, new __());
    };
})();
var Base = /** @class */ (function () {
    function Base() {
    }
    return Base;
}());
var SubClass = /** @class */ (function (_super) {
    __extends(SubClass, _super);
    function SubClass() {
        return _super !== null && _super.apply(this, arguments) || this;
    }
    return SubClass;
}(Base));

target es3

var __extends = (this && this.__extends) || (function () {
    var extendStatics = Object.setPrototypeOf ||
        ({ __proto__: [] } instanceof Array && function (d, b) { d.__proto__ = b; }) ||
        function (d, b) { for (var p in b) if (b.hasOwnProperty(p)) d[p] = b[p]; };
    return function (d, b) {
        extendStatics(d, b);
        function __() { this.constructor = d; }
        d.prototype = b === null ? Object.create(b) : (__.prototype = b.prototype, new __());
    };
})();
var Base = /** @class */ (function () {
    function Base() {
    }
    return Base;
}());
var SubClass = /** @class */ (function (_super) {
    __extends(SubClass, _super);
    function SubClass() {
        return _super !== null && _super.apply(this, arguments) || this;
    }
    return SubClass;
}(Base));

結論

targetがes6以上で指定されているソースのclass(npm_modules配下の奴とか)を継承した場合、こちらのtargetがes5以下の設定だと完全に死ぬっぽい。
classを関数として呼ぼうとしましたってエラーで。

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