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paizaラーニング「二次元配列での要素の検索 Python3編」

Posted at

私の解答

n, k = map(int, input().split())
a = [input().split() for _ in range(n)]

for i in range(n):
    for j in range(k):
        if int(a[i][j]) == 1:
            print(i+1, j+1)

私は数値として扱っていますが、解答例は文字として扱っています。

解答例

n, k = map(int, input().split())
a = [input().split() for _ in range(n)]

for i in range(n):
    for j in range(k):
        if a[i][j] == "1":
            print(i + 1, j + 1)
            break
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