Ruby | Delete only the first element in the array (get everything after the second line)

Solution

drop it.

 ['A','B','C','D','E'].drop(1) # => ["B", "C", "D", "E"] 

problem

shift return value

If you shift the array, the extracted element will be the return value. It is not a remaining element.

 ['A','B','C','D','E'].shift => "A" 

shift!

shift is destructive in the first place. So there is no shift!

 ['A','B','C','D','E'].shift! # => NoMethodError: undefined method `shift!' for ["A", "B", "C", "D", "E"]:Array 

Temporary variable

I can get the value I want. I have to write three lines.

 alphabets = ['A','B','C','D','E'] alphabets.shift alphabets # => ["B", "C", "D", "E"] 

past

So far, I have been asking [1..-1] for arrays.

 ['A','B','C','D','E'][1..-1] # => ["B", "C", "D", "E"] 

1 means the second of the array. (Not 2 ) -1 means the end of the array.

environment

• Ruby 2.2.4

Acknowledgment

• @pinzolo who taught me drop
• @scivola who pointed out that shift is destructive in the first place

Original by

Ruby | 配列で最初の要素だけを削除する ( 2行目以降を全て得る )

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