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9. Palindrome Number

Java
アルゴリズム
algorithm
leetcode
Brute-force

Last updated at 2022-12-08Posted at 2022-12-08

アプローチ

Brute force

class Solution {
    public boolean isPalindrome(int x) {
        if (x < 0) {
            return false;
        }
        
        String a = String.valueOf(x);

        StringBuilder b = new StringBuilder();

        for (int i = a.length() - 1; i >= 0; i--) {
            b.append(a.charAt(i));
        }
        return b.toString().equals(a);        
    }
}

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