SwiftでRangeからn回繰り返して、異なる結果のArrayを取得する

例えば、異なるUUID10個の配列が欲しい場合

(0..<10).map { _ in UUID().uuidString }

# (10 elements) ["F4B0C448-0E10-40BF-9AAA-70FFEBB3307C", "16EC149E-7B1B-4A29-B32A-ED02B65FEC93", "398F2B91-9C9D-4526-8969-BAAD8B5A458E", "2C55C5B2-8110-410D-A8C9-34244F5BFA5B", "B0FB472D-12DB-4321-87E0-75C0E745ED39", "48A8D711-3AE8-4C76-A958-2AB02304ED63", "62B6EE3B-8EEB-47C7-A4FD-501D9CB34FE1", "71719DFB-D2D5-4005-B96E-0C8A5CDBE805", "61FB03FE-A233-4073-B72C-236D8EA5529C", "380133B2-96AB-43F6-B4D6-E6454895375C"]

ちなみに↓はすべて同じUUIDが返ってくる

Array(repeating: UUID().uuidString, count: 10)

# (10 elements) ["2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479", "2167A236-2797-487B-9B85-63FA3BFCC479"]

とりあえず思いついて動いたのでメモ。他に良い方法があれば教えてください。