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Rubyで素数を求める

Last updated at Posted at 2016-03-23

Rubyの練習がてらに素数判定のプログラムを書いた。

1から1000までの整数から素数を求める

PrimeJudging
primeNumbers = []
(1..1000).each do |i|
  next if i == 1

  if i == 2
    primeNumbers.push(i)
    next
  end

  judge = true
  primeNumbers.each do |number|
      if i % number == 0
        judge = false
        break
      end
  end

  primeNumbers.push(i) if judge

end
puts primeNumbers

結果

Result
2
3
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
83
89
97
101
103
107
109
113
127
131
137
139
149
151
157
163
167
173
179
181
191
193
197
199
211
223
227
229
233
239
241
251
257
263
269
271
277
281
283
293
307
311
313
317
331
337
347
349
353
359
367
373
379
383
389
397
401
409
419
421
431
433
439
443
449
457
461
463
467
479
487
491
499
503
509
521
523
541
547
557
563
569
571
577
587
593
599
601
607
613
617
619
631
641
643
647
653
659
661
673
677
683
691
701
709
719
727
733
739
743
751
757
761
769
773
787
797
809
811
821
823
827
829
839
853
857
859
863
877
881
883
887
907
911
919
929
937
941
947
953
967
971
977
983
991
997

追記

素数判定のメソッド1

Method1
def isPrime(i)
  # 1は素数ではない
  return false if i == 1

  # 2は素数
  return true if i == 2

  primeNumbers = [2]
  judge = true

  # 入力値より小さい素数の集合を求めながら、入力値が素数であるか判定する
  (3..i).each do |j|
      judge = true
      primeNumbers.each do |number|
          if j % number == 0
            judge = false
            break
          end
      end
      primeNumbers.push(j) if judge
  end

  return judge
end

追記

素数判定のメソッド2

Method2
def isPrime2(i)
  # 1は素数ではない
  return false if i == 1

  # 2は素数
  return true if i == 2

  judge = true
  (2..i).each do |j|
      # root i までで十分
      break if j > i**0.5 
      if i % j == 0
            judge = false
            break
      end
   end
   return judge   
end
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