abc198のメモ

A

N = int(input())
ans = 0
if N<2:
    ans = 0
else:
    ans = N - 1
print(ans)

B

N = input()
L = len(N)

for i in range(L):
    if int(N[-1]) == 0:
        N = N[0:L-i-1]

for i in range(int(len(N)/2)):
    if N[i] != N[len(N)-i-1]:
        print("No")
        exit()

print("Yes")

C

import math

R, X, Y = [int(a) for a in input().split()]
dis = math.sqrt(X**2 + Y**2)

if dis < R:
    print(2)
elif dis == R:
    print(1)
else:
    print(math.ceil(dis/R))

D

当日は時間切れで提出できず、残念。
後日じっくり考えたらできた。
itertoolsって初めて使ったけど、競プロで今後も役に立ちそう。

PythonではLTE。同じコードでPypyだと通りました

import itertools

S = []
strings = []
N = []
for i in range(3):
    S.append(input())
    N.append(list())
    for j in range(len(S[i])):
        strings.append(S[i][j])
        N[i].append(0)

str_set = set(strings)
str_list = list(str_set)

if len(str_set) > 10:
    print("UNSOLVABLE")
    exit()

for v in itertools.permutations(range(10), len(str_set)):
    if v[str_list.index(S[0][0])] == 0 or  v[str_list.index(S[1][0])] == 0 or  v[str_list.index(S[2][0])] == 0:
        continue
    N123 = [0, 0, 0]
    for i in range(3):
        num = ""
        for j in range(len(S[i])):
            num += str(v[str_list.index(S[i][j])])
        N123[i] = int(num)
    if (N123[0]+N123[1] == N123[2]) and (N123[0] != 0)and (N123[1] != 0)and (N123[2] != 0):
        for x in N123:
            print(x)
        exit()

print("UNSOLVABLE")