python3で８進数をバイナリ保存するメモ

solv.py

import struct

with open('./flag_clip', 'r') as rf:
    with open('./flag_out', 'wb') as wf:
        rtxt = rf.read().replace('\n',' ')
        for t in rtxt.split():
            #print(t, '=>', int(t, 8))
            wf.write(struct.pack("B", int(t, 8)))
print('end')