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ABC384Bをjavascriptで解いた

Posted at

今日の問題

↑押してください。

自分の回答(javascript)

function Main(input){
    min = 1e18
    max = -1e18
    let abc = "abcdefghijklmnopqrstuvwxyz".split("")
    let ABC = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".split("")
    let f = 2
    if(f == 0){
      input = parseInt(input.trim())
    }
    if(f == 1){
      input = input.trim().split("\n").map((a)=>parseInt(a))
    }
    if(f == 2){
      input = input.trim().split("\n").map((a)=>a.split(" ").map((b)=>parseInt(b)))
    }
    //ここより上は定型文です。
   let [n,r] = input.shift()
   for(let i = 0;i<n;i++){
     if(input[i][0] == 1){
       if(r >= 1600&&r<=2799){
         r += input[i][1]
       }
     }
     if(input[i][0] == 2){
       if(r >= 1200&&r<=2399){
         r += input[i][1]
       }
     }
   }
   console.log(r)
   }
  Main(require("fs").readFileSync(0, "utf8"));
  

工夫した点

順番に処理していきます。レートの更新によって、ratedかunratedかが変わるので注意が必要です。ARCが参加できなくなって悲しいです。ARCのほうが判定がよく出ていたので残念(泣)

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