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Typescriptでnew演算子を使うobjectのTypeを定義したいとき

Posted at

tl;dr

new () propertyで指定できます。

サンプル

test.ts
interface TestConstructor {
  new (a: string, b: number): Test;
}

// こんな事したい場合は参照ないことが多いので
declare const Test: TestConstructor;

const test = new Test('aaa', 100);
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