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コマンドの実行結果を入れ子にする 

バッククォートを使うと無理だけど、

: pwdの結果をsedで置換した結果を…
cd /Users/foo
echo parent dir=`echo `pwd` | sed -e "s/foo//"`
zsh: parse error near `|'
zsh: parse error in command substitution

$()を使うと、

echo parent dir=$(echo `pwd` | sed -e "s/\/foo//")
parent dir=/Users

: pwdの結果をsedで置換した結果をsedで置換し...
echo root dir=$(echo $(echo `pwd` | sed -e "s/\/foo//") | sed -e "s/Users//")
root dir=/

何重にでもできる。

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18
Help us understand the problem. What are the problem?