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bashの計算式で、秒数をHH:MM:SSフォーマットに変換する

Last updated at Posted at 2015-06-01

ほぼこれ。

ただし、上記記事のコードだと$iを上書きしてしまうので、そこだけ直した。

%は余りを求める。/は余りを除いた商を求める。

i=6789
((sec=i%60, min=(i%3600)/60, hrs=i/3600))
timestamp=$(printf "%d:%02d:%02d" $hrs $min $sec)
echo $timestamp

総計を60*60で割った余りをさらに60で割ることで、分の位を求める。

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