Undefined type 'App\Controller\Request'というエラーの対処法

Posted at 2024-05-11

問題のコード

<?php

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
// use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Routing\Annotation\Route;

class HelloController extends AbstractController
{
    #[Route('/hello', name:'hello')]
    public function index(Request $request)
    {   
    $name = $request->get('name');
        $pass = $request->get('pass');
        $result = '<html><body><ol>';
        $result .= '<h1>Parameter</h1>';
        $result .= '<p>name: ' . $name . '</p>';
        $result .= '<p>pass: ' . $pass . '</p>';
        $result .= '</body></html>';

        return new Response($result);
    }
}

解決方法

<?php

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
+ use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Routing\Annotation\Route;

class HelloController extends AbstractController
{
    #[Route('/hello', name:'hello')]
    public function index(Request $request)
    {   
    $name = $request->get('name');
        $pass = $request->get('pass');
        $result = '<html><body><ol>';
        $result .= '<h1>Parameter</h1>';
        $result .= '<p>name: ' . $name . '</p>';
        $result .= '<p>pass: ' . $pass . '</p>';
        $result .= '</body></html>';

        return new Response($result);
    }
}

use Symfony\Component\HttpFoundation\Requestをインポートするだけでした。

これでhttp://127.0.0.1:8000/hello?name=itiro&pass=flowerにアクセスすると無事にページが表示されました。

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