Parallel and orthogonal judgement with dot and cross from input for two four points

n = input
a = []
for i in range(n):
  a.append(map(int, raw_input().split()))
for aa in a:
  an = np.array(aa).reshape(4,2)
  s1 = an[1]-an[0]
  s2 = an[3]-an[2]
  dot = np.dot(s1,s2)
  cross = np.cross(s1,s2)
  if (dot==0):
    print("1")
  elif (cross==0):
    print("2")
  else:
    print("0")

3
0 0 3 0 0 2 3 2
0 0 3 0 1 1 1 4
0 0 3 0 1 1 2 2
2
1
0

Refs.

http://d.hatena.ne.jp/pashango_p/20090714/1247590272
https://qiita.com/lethe2211/items/6cbade2bc547649bc040