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1行素数判定コード (Python3)

Last updated at Posted at 2020-03-07

1行素数判定コード

知人のmarienが1行素数判定のコードを作成してくれたのでその紹介です。
(このコードはとにかく1行で書くことを目的としたので計算速度とかは全く気にしておりません)

print('not sosu') if 0 in [(i + 1 + num) % num for i, num in enumerate(reversed(range(2, int(input()))))] else print('sosu')
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