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行の数値の平均をとる

Last updated at 2014-12-27Posted at 2014-12-25

NF>1 {
  i=1;
  sum=0;
  while(i <= NF) {
    sum += $i;
    i++;
  }
  print sum/NF;
}

test

> echo '1 2 3 4 5' | awk 'NF>1 {i=1;sum=0; while(i <= NF) {sum += $i; i++;} print sum/NF;}'
3

(12/27編集) heliac2000さんのコメントを適用