a は返らないことに注目。
[1] pry(main)> def m
[1] pry(main)* a = 1
[1] pry(main)* b = 2
[1] pry(main)* a
[1] pry(main)* b #最後に評価された b がメソッドの戻り値
[1] pry(main)* end
=> :m
[2] pry(main)> m
=> 2 # 先に評価された a は返らない。
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