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AtCoder Python チートシート

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入力

一行だけ取る

Input script 結果
abcde s=input() s='abcde'
abcde s=list(input()) s=['a', 'b', 'c', 'd', 'e']
5(1つだけ) a=int(input()) a=5
1 2 x,y = map(int,input().split()) x=1,y=2
1 2 3 4 5 ... n li = input().split() li=['1','2','3',...,'n']
1 2 3 4 5 ... n li = list(map(int,input().split())) li=[1,2,3,4,5,...,n]
FFFTFTTFF li = input().split('T') li=['FFF', 'F', '', 'FF']

複数行取る

patern 1

input.txt
3
a
b
c
input.py
n=int(input())
string_list=[input() for i in range(n)]
#string_list<-['a','b','c']

patern 2

input.txt
3
1 2 2 3 1 5
4 5 3 4 1 2
2 3 5 6 0 2
input.py
n = int(input())
for i in range(n):
    listA=list(map(int,input().split()))
    #ここに逐次処理を書けばいいと思う。
input.py
n = int(input())
for i in range(n):
    listA.append(list(map(int,input().split())))
print(listA)
#[[1, 2, 2, 3, 1, 5], [4, 5, 3, 4, 1, 2], [2, 3, 5, 6, 0, 2]]

出力

一行だけ

Input script OutPut
s = "abcde" print(s) abcde\n
s = "abcde" print(s,end="") abcde
a = 1, b = 2 print(a/b) 0.5\n
a = 1, b = 2 print("%lf" % (a/b)) 0.500000\n
a = 1, b = 2 print("%.1lf" % (a/b)) 0.5\n
a = 1, b = 2 print(str(a+b)+"ですね" 0.5くらいかな\n

複数

patern 1

output.txt
a
b
c
input.py
n=["a","b","c"]
for i in n:
    print(i)

patern 2

output.txt
1 2 2 3 1 5
4 5 3 4 1 2
2 3 5 6 0 2
input.py
n = [[1, 2, 2, 3, 1, 5], [4, 5, 3, 4, 1, 2], [2, 3, 5, 6, 0, 2]]
s = 3
t = 6
for i in range(s):
    for j in range(t-1):
        print(n[i][j],end = " ")
    print(n[i][t-1])
input.py
n = [[1, 2, 2, 3, 1, 5], [4, 5, 3, 4, 1, 2], [2, 3, 5, 6, 0, 2]]
s = 3
t = 6
for i in range(s):
    for j in range(t-1):
        print(*n[i])

小数点

一行だけ

a = 0.364364

print(a) #0.364364
print("{:.6f}".format(a)) #0.364364
print("{:.4f}".format(a)) #0.3644 小数点第4位に丸めることもできる。

進数変更

b = 810

print("{:b}".format(b)) #1100101010  2進数表記 
print("{:o}".format(b)) #1452        8進数表記
print("{:x}".format(b)) #32a         16進数小文字表記
print("{:X}".format(b)) #32A         16進数大文字表記

二分探索

li = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
s = 0
t = len(li)
def ch(x):
    y = 13
    if x > y:
        return 0
    else:
        return 1
while True:
    p = int((s+t)/2)
    pp = ch(p)
    if pp == 0:
        t = p
    elif pp == 1:
        s = p
    print(s,t)
    if s + 1 == t:
        break
ans = s

bit探索

li = [1,2,3,4,5,6,7,8,9]
for i in range(2**len(li)):
    s = "{:b}".format(i)
    s = list(s)
    s = [int(i) for i in s]
    s = [0]*(len(li) - len(s)) + s
    o = 0
    for j in range(len(s)):
        o = o + s[j] * li[j]
    #処理を

sort

l = [3, 1, 4, 5, 2]

l.sort()
print(l)
# [1, 2, 3, 4, 5]

l.sort(reverse=True)
print(l)
# [5, 4, 3, 2, 1]
l = [3, 1, 4, 5, 2]

l_sorted = sorted(l)
print(l_sorted) # [1, 2, 3, 4, 5]
print(l)        # [3, 1, 4, 5, 2]

l_reverse_sorted = sorted(l, reverse=True)
print(l_reverse_sorted) # [5, 4, 3, 2, 1]
l = [-3, 1, 4, -5, 2]
print(sorted(l)) # [-5, -3, 1, 2, 4]
print(sorted(l, key=abs)) # [1, 2, -3, 4, -5]

l = ['b', 'cc', 'aaa']
print(sorted(l)) # ['aaa', 'b', 'cc']
print(sorted(l, key=len)) # ['b', 'cc', 'aaa']

l = ['banana', 'cherry', 'apple']
print(sorted(l)) # ['apple', 'banana', 'cherry']

l.sort()
print(l) # ['apple', 'banana', 'cherry']
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