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ABC195 C - Comma を解いた

Posted at

abc195_1.png
abc195_2.png

右から数えて 1 つ目のコンマ
右から数えて 2 つ目のコンマ
右から数えて 3 つ目のコンマ
右から数えて 4 つ目のコンマ
右から数えて 5 つ目のコンマ

と分けてカウントしてみた。

abc195c.py
N = int(input())
cnt = 0
if len(str(N))>3:
    cnt += N-999
    if len(str(N))>6:
        cnt += N-999999
        if len(str(N))>9:
            cnt += N-999999999
            if len(str(N))>12:
                cnt += N-999999999999
                if len(str(N))>15:
                    cnt += N-999999999999999

print(cnt)
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