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a == 1 and a == 2 and a == 3 がTrueになるPythonスクリプト

Posted at

QiitaでRuby版の記事を見かけたので,Pythonでも作ってみました。

ソースコード

>>> class Test:
        def __eq__(self, foo):
                return True

>>> a = Test()
>>> if a==1 and a==2 and a==3:
        print('Hello Qiita')

Hello Qiita
>>> 

ポイント(?)

作るにあたって,少し学んだことがあったのでメモしておきます。

###==演算子について
Pythonでは,== 演算子は__eq__メソッドで定義されています。もし,定義されていない場合,==isと同じ扱いになります。

>>>class Test2:
        pass

>>> b = Test2()
>>> c = Test2()
>>> d = b
>>> b == c
False
>>> b == b
True
>>> b is b
True
>>> b == d
True
>>> b is d
True

参考

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