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Powershellでフォルダ内のファイルをフルパスで取得する

Last updated at Posted at 2015-12-31
# 例// C:\work配下のファイルをフルパスで取得
#  C:\workを変数格納
$DIRFOL = "C:\work"


# dir = C:\work配下をリスト取得(Get-Childitem)
 ## -Receurse = 再帰的に取得する 
 ## -File = ファイルのみ取得する(フォルダ除く)
$DIRFILE = dir -Recurse -File ${DIRFOL}


# .fullname = フルパスで取得し表示する
$FULLNM = ${DIRFILE}.fullname

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