0
0

More than 1 year has passed since last update.

アプローチ

  • binary search
class Solution {
    public boolean searchMatrix(int[][] matrix, int target) {
        for (int[] m : matrix) {
            Arrays.sort(m);

            int left = 0;
            int right = m.length - 1;

            while (left <= right) {
                int mid = (left + right) / 2;
                if (m[mid] == target) {
                    return true;
                }

                if (m[mid]  < target) {
                    left = mid + 1;
                } else {
                    right = mid - 1;
                }
            }
        }
        return false;
    }
}
0
0
0

Register as a new user and use Qiita more conveniently

  1. You get articles that match your needs
  2. You can efficiently read back useful information
  3. You can use dark theme
What you can do with signing up
0
0