\begin{align}
\qquad &ax^2+bx+c = 0 \\
\Leftrightarrow &\quad x^2 + \frac{b}{a}x = - \frac{c}{a} \\
\Leftrightarrow &\quad x^2 + \frac{b}{2a} x + \frac{b^2}{4a^2} = \frac{b^2}{4a^2} - \frac{c}{a} \\
\Leftrightarrow &\quad (x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2} \\
\Leftrightarrow &\quad x + \frac{b}{2a} = \pm \frac{\sqrt{b^2-4ac}}{2a} \\
\therefore &x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}
\end{align}
\begin{align}
\qquad &ax^2+bx+c = 0 \\
\Leftrightarrow &\quad x^2 + \frac{b}{a}x = - \frac{c}{a} \\
\Leftrightarrow &\quad x^2 + \frac{b}{2a} x + \frac{b^2}{4a^2} = \frac{b^2}{4a^2} - \frac{c}{a} \\
\Leftrightarrow &\quad (x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2} \\
\Leftrightarrow &\quad x + \frac{b}{2a} = \pm \frac{\sqrt{b^2-4ac}}{2a} \\
\therefore &x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}
\end{align}