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今日のsed: 任意の文字列以降の行をすべて出力したい

Last updated at Posted at 2016-03-03

やりたいこと

こういうファイルがあったとして、bar 以降の行だけ出力したい。

qiita.txt
hoge
foo
bar
buzz
piyo

一度しか出現しないケース

それsedで出来るよ。

cat /tmp/qiita.txt | sed -n '/bar/,$p'
bar
buzz
piyo

これでも良さそうだけど、超絶カッコ悪い。

cat /tmp/qiita.txt | tac | sed '/bar/q' | tac
bar
buzz
piyo

2回以上出現するケース

2回以上出現するケースで使い分けたらいいよ。

qiita2.txt
hoge
foo
bar
buzz
piyo
hoge
foo
bar
buzz
piyo
  • 初出以降全部出力
cat /tmp/qiita2.txt | sed -n '/bar/,$p'
bar
buzz
piyo
hoge
foo
bar
buzz
piyo
  • 最後の出現以降全部出力
cat /tmp/qiita2.txt | tac | sed '/bar/q' | tac
bar
buzz
piyo
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