count(a + l, a + r, x ) ( xの個数を判定)
int a[10] = {1, 2, 3, 4, 1, 2, 3, 1, 2, 1};
cout << count(a, a + 10, 1) << endl;
More than 1 year has passed since last update.
Register as a new user and use Qiita more conveniently
- You get articles that match your needs
- You can efficiently read back useful information
- You can use dark theme