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numpyの2次元リストから1次元リストを検索し、行番号を取得する

Last updated at Posted at 2019-04-19

numpyで2次元リストから1次元リストそのものを検索し、行番号を取得する。

import numpy as np

a=np.random.randint(0,2,(10,2))
b=np.random.randint(0,2,2)
c=np.where(np.all(a==b,axis=1))
print('a={}'.format(a))
print('b={}'.format(b))
print('c={}'.format(c[0]))

こんな感じで出力される。

a=[[0 1]
 [0 1]
 [0 1]
 [1 1]
 [0 0]
 [1 1]
 [0 0]
 [0 0]
 [0 0]
 [1 0]]
b=[1 0]
c=[9]

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