reverse(a, a + N) (a[0] ~ a[N-1] を逆順にする)
reverse(a + l, a + r) (a[l] ~ a[r-1] を逆順にする)
計算量は O(N)
int a[8] = {8, 3, 7, 1, 4, 6, 2, 5};
reverse(a + 2, a + 7);
{8, 3, 2, 6, 4, 1, 7, 5}
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