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ABC - 010 - A&B&C

Posted at

#AtCoder ABC 010 A&B&C
AtCoder - 010

#A - ハンドルネーム

	private void solveA() {
		out.println(next() + "pp");
	}

#B - 花占い

  • 最初分岐して・・・ってやったけど、よく考えたら2と3の最小公倍数の6の余りで分岐したほうが読みやすかった
    • コメントアウトしているif文の方もACではある
	private void solveB() {
		int n = nextInt();
		int[] wk = IntStream.range(0, n).map(i -> nextInt()).toArray();
		int res = Arrays.stream(wk).reduce(0, (sum, i) -> {
			switch (i % 6) {
			case 1:
				return sum;
			case 2:
				return ++sum;
			case 3:
				return sum;
			case 4:
				return ++sum;
			case 5:
				return sum += 2;
			case 0:
				return sum += 3;
			}
			//			if (i % 2 == 1) {
			//				switch (i % 3) {
			//				case 0:
			//				case 1:
			//					return sum;
			//				case 2:
			//					return sum += 2;
			//				}
			//
			//			} else {
			//				switch (i % 3) {
			//				case 0:
			//					return sum += 3;
			//				case 1:
			//				case 2:
			//					return ++sum;
			//				}
			//			}

			return sum;
		});

		out.println(res);
	}

#C - 浮気調査

  • 三平方の定理を久しぶりに見た
  • ごり押しでも通るんだーって思った後に解法見たら楕円の定理でも解けるとな。。。わからん。。。
	private void solveC() {
		int sX = nextInt();
		int sY = nextInt();
		int gX = nextInt();
		int gY = nextInt();
		int t = nextInt();
		int v = nextInt();
		int n = nextInt();

		for (int i = 0; i < n; i++) {
			int tmpX = nextInt();
			int tmpY = nextInt();
			double total = (Math.hypot(Math.abs(tmpX - sX), Math.abs(tmpY - sY))
					+ Math.hypot(Math.abs(tmpX - gX), Math.abs(tmpY - gY)));
			if (total <= t * v) {
				out.println("YES");
				return;
			}
		}

		out.println("NO");
	}
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