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整数配列と整数ターゲットが与えられた場合、2つの数値の合計がターゲットと同値になり、indexを返却する

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####趣向
ターケットの値と配列の中のいずれかの値を足した数が同値の場合のindexを
返却する必要があり、結構悩みました。

####例
nums = [2,7,11,15], target = 9の場合[0,1]
nums = [3,2,4], target = 6の場合[1,2]
nums = [3,3], target = 6の場合[0,1]
nums = [3,0,3], target = 6の場合[0,2]

python3
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        stay = {}
        for index, number in enumerate(nums):
            difference = target - number
            if difference in stay:
                return [stay[difference], index]
            else:
                stay[number] = index

結構悩みましたね^^;
これ以外の実装方法も色々とありそうですが、、これしか浮かびませんでした。

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