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csv をパースする JavaScript

Last updated at Posted at 2019-03-02

車輪の再発明です

CSV の仕様

RFC 4180

改行は CRLF でなければならないそうです。

実装例

function parseCSV(d) {
	let t = d.replace(/\r\n$/u, '')
	const r = [[]]
	let c = 0
	let l, m, n
	while ([l, m, n] = /^(|[^",](?:[^,\r]|\r[^,\n])*\r?|"(?:[^"]|"")*")(,|\r\n|$)/u.exec(t)) {
		if ('"' === m[0] && '"' === m[m.length - 1]) m = m.slice(1, -1)
		r[c].push(m.replace(/""/gu, '"'))
		if (!n) break
		if (',' !== n) r[++c] = []
		t = t.substring(l.length)
	}
	return r
}

実装例2

\n\r も改行とみなす方が便利かと思います。

function parseCSV(d) {
	let t = d.replace(/(\r?\n|\r)$/u, '')
	const r = [[]]
	let c = 0
	let l, m, n
	while ([l, m, n] = /^(|[^",][^,\r\n]*|"(?:[^"]|"")*")(,|\r?\n|\r|$)/u.exec(t)) {
		if ('"' === m[0] && '"' === m[m.length - 1]) m = m.slice(1, -1)
		r[c].push(m.replace(/""/gu, '"'))
		if (!n) break
		if (',' !== n) r[++c] = []
		t = t.substring(l.length)
	}
	return r
}
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