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bashで文字列の前後の空白を除去する関数を作る

Bash

Last updated at 2019-09-25Posted at 2019-09-25

functions.sh

trim_string() {
    # Usage: trim_string "   example   string    "
    : "${1#"${1%%[![:space:]]*}"}"
    : "${_%"${_##*[![:space:]]}"}"
    printf '%s\n' "$_"
}

使う

source function.sh
trim_string " test  "

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