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@peroon(peroon)

Pythonでリストの連続する要素でグループ化するgroupby

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from itertools import groupby

a = [1, 2, 3, 2, 2, 2, 3, 3, 4, 4, 4, 3, 1, 1]
a = sorted(a)

# 連続する要素をグループ化する
for key, group in groupby(a):
    print list(group)

実行結果

[1, 1, 1]
[2, 2, 2, 2]
[3, 3, 3, 3]
[4, 4, 4]
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