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C言語 九九の結果を表示するプログラム

Last updated at Posted at 2018-07-05

#はじめに
C言語での九九の結果を表示するプログラムを作成してみました。

#ソースコード

#include <stdio.h>
 
int main(void){
 
  /* カウンタ変数の宣言 */
  int a, b;
 
  /* 九九の計算 */
  for(a=1;a<10;++a) {
    for(b=1;b<10;++b) {
      if(b==9)
        printf("%3d\n", a*b);
      else
        printf("%3d", a*b);
    }
  }
 
  return 0;
}


#実行結果

  1  2  3  4  5  6  7  8  9
  2  4  6  8 10 12 14 16 18
  3  6  9 12 15 18 21 24 27
  4  8 12 16 20 24 28 32 36
  5 10 15 20 25 30 35 40 45
  6 12 18 24 30 36 42 48 54
  7 14 21 28 35 42 49 56 63
  8 16 24 32 40 48 56 64 72
  9 18 27 36 45 54 63 72 81
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