sympyで円と円の交点

#sympyで円と円の交点
import sympy.geometry as sg

center = sg.Point(0,0)
radius = 10
circle1 = sg.Circle(center, radius)

center = sg.Point(10,0)
radius = 10
circle2 = sg.Circle(center, radius)

result = sg.intersection(circle1,circle2 )

print(result)
print(len(result))
print(float(result[0].x),float(result[0].y),float(result[1].x),float(result[1].y))

#(結果)#pycharm
#[Point2D(5, 5*sqrt(3)), Point2D(5, -5*sqrt(3))]
#2
#5.0 8.660254037844387 5.0 -8.660254037844387
#
#(結果)#SymPy Live　Online Shell#精度がいいかも 
#http://live.sympy.org/
#[Point2D(5, 5*sqrt(3)), Point2D(5, -5*sqrt(3))] 
#2 
#(5.0, 8.6602540378443873, 5.0, -8.6602540378443873)
#
# (参考)#Pythonで円とか線とか線分の交点を求める＋普通の値に戻す
# http://kamiwo-koete.hatenablog.jp/entry/2014/12/23/193018

参考

3次元:3つの球の交点計算