何かいい方法ないですか?
(参考)数学II・数学Ｂ問題
https://www.asahicom.jp/edu/center-exam/shiken2020/pdf2c49z2id/suugaku2_01.pdf
(参考)センター試験解答速報2020＜予備校の東進 ＜「基本的な内容である。」そうです。
https://www.toshin.com/center/sp/
wolframalphaでやってみたい
アイウ=====================
?
エ=======================
?
オカキク================
sin(x)>sqrt(3) cos(x - π/3),0<=x<2*π
https://www.wolframalpha.com/input/?i=sin%28x%29%3Esqrt%283%29+cos%28x+-+%CF%80%2F3%29%2C0%3C%3Dx%3C2*%CF%80&lang=ja
--->(2 π)/3<x<(5 π)/3
ケコサシ===============
25c**2-35c+k=0,25s**2-35s+k=0,c2+s2=1,0<=c<=1,0<=s<=1
https://www.wolframalpha.com/input/?i=25*c**2-35*c%2Bk%3D0%2C25*s**2-35*s%2Bk%3D0%2Cc**2%2Bs**2%3D1%2C0%3C%3Dc%3C%3D1%2C0%3C%3Ds%3C%3D1&lang=ja
--->c = 3/5, k = 12, s = 4/5
--->c = 4/5, k = 12, s = 3/5
--->c = 1/sqrt(2), k = 35/sqrt(2) - 25/2, s = 1/sqrt(2)
25c**2-35c+12=0,25s**2-35s+12=0,c2+s2=1,0<=c<=1,0<=s<=1,s>=c
https://www.wolframalpha.com/input/?i=25*c**2-35*c%2B12%3D0%2C25*s**2-35*s%2B12%3D0%2Cc**2%2Bs**2%3D1%2C0%3C%3Dc%3C%3D1%2C0%3C%3Ds%3C%3D1%2Cs%3E%3Dc&lang=ja
--->c = 3/5, s = 4/5
ソ=====================
25cos(t)**2-35cos(t)+12=0,25sin(t)**2-35sin(t)+12=0,0<=t<=pi/2,sin(t)>=cos(t)
wolframalpha.com/input/?i=25cos%28t%29**2-35cos%28t%29%2B12%3D0%2C25sin%28t%29**2-35sin%28t%29%2B12%3D0%2C0<%3Dt<%3Dpi%2F2%2Csin%28t%29>%3Dcos%28t%29&lang=ja
--->t = 2 tan^(-1)(1/2)
2 tan^(-1)(1/2)*180/pi
https://www.wolframalpha.com/input/?i=2+tan%5E%28-1%29%281%2F2%29*180%2Fpi&lang=ja
--->53.130....
180/4
--->45
180/3
--->60
Sympy onlineでやってみたい
(参考)SymPy Live
https://live.sympy.org/
アイウ==================================
simplify(sqrt(3) *cos(x - pi/3)-sin(x))
print(expand(sqrt(3) cos(x - pi/3), trig=True))
--->3sin(x)/2 + sqrt(3)*cos(x)/2
エ======================================
simplify(sqrt(3) *cos(x - pi/3)-sin(x))
print( simplify(sqrt(3) *cos(x - pi/3)-sin(x)) )
--->sin(x + pi/3)
オカキク=================================
solve(sin(x + pi/3)<0)
print(solve(sin(x + pi/3)<0))
--->(2pi/3 < x) & (x < 5pi/3)
ケコサシ==================================
ソ========================================
Sympy pythonでやってみたい
作業中