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compareToの大小比較について

Last updated at Posted at 2019-05-24

#CompareToについて値の結果、どの比較がどの値になるか忘れてしまうことがあるので、備忘録。

①文字列で比較する場合はcompareTo()


public class Test {
	public static void main(String[] args) {
		 String a = "a";
		 String b = "b";
		 System.out.println(a.compareTo(b));
		 System.out.println(b.compareTo(a));
		 System.out.println(a.compareTo(a));
	}
}

下が実行結果です。

-1
1
0

辞書的に文字の位置が離れている場合に、-1か1を返します。
aはbの前なので-1
bはaのあとなので1
同一の場合は0

②数値で比較する場合はInteger.compare()


public class Test {
	public static void main(String[] args) {
		 int one = 1;
		 int two = 2;
		 System.out.println(Integer.compare(one,two));
		 System.out.println(Integer.compare(two,one));
		 System.out.println(Integer.compare(one,one));
	}
}

下が実行結果です。

-1
1
0

単純に計算結果。
1-2=-1
2-1=1
1-1=0です。

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