c puzzle book basic type 1

bash

$ gcc b51.c
bt1.c:11:24: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘char *’ [-Wformat=]
   11 |         PRINT(d, string);           // ポインタを %d で表示 → 型不一致のため %p で表示
      |                  ~~~~~~^
      |                  |
      |                  char *
bt1.c:3:34: note: in definition of macro ‘PRINT’
    3 | #define PRINT(format, x) printf(#x " = %" #format "\n", x)
      |     

bt1.c

#include <stdio.h>

#define PRINT(format, x) printf(#x " = %" #format "\n", x)

int main()
{
	int integer = 5;
	char character = '5';       // ASCII 53
	char *string = "5";

	PRINT(p, string);           // ポインタを %d で表示 → 型不一致のため %p で表示 
	PRINT(d, character);        // character = 53
	PRINT(d, integer);          // integer = 5

	PRINT(s, string);           // string = 5
	PRINT(c, character);        // character = 5
	PRINT(c, integer = 53);     // integer = 5 (ASCII)

	PRINT(d, ('5' > 5));        // '5' (53) > 5 → 1

	int sx = -8;
	unsigned int ux = -8;

	PRINT(o, sx);               // sx = 37777777770（2の補数）
	PRINT(o, ux);               // ux = 37777777770（unsignedでも同じビット表現）

	PRINT(o, sx >> 3);          // 算術シフト（符号あり）
	PRINT(o, ux >> 3);          // 論理シフト（符号なし）

	PRINT(d, sx >> 3);
	PRINT(d, ux >> 3);

	return 0;
}

/*
nagai@compB05:~/Conpairu$ ./a.out
string = 0x564be7928004
character = 53
integer = 5
string = 5
character = 5
integer = 53 = 5
('5' > 5) = 1
sx = 37777777770
ux = 37777777770
sx >> 3 = 37777777777
ux >> 3 = 3777777777
sx >> 3 = -1
ux >> 3 = 536870911