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Ginqで2つの連想配列をJoinする例

Last updated at Posted at 2015-01-03
{
    "require": {
        "ginq/ginq": "dev-master"
    }
}
<?php
require_once 'vendor/autoload.php';

// 商品カテゴリ
$categories = array(
    array('id' => 1, 'name' => '果物'),
    array('id' => 2, 'name' => '魚'),
);
// 商品データ
$items = array(
    array('id' => 1, 'name' => 'りんご', 'price' => 100, 'category' => 1),
    array('id' => 2, 'name' => 'みかん', 'price' =>  80, 'category' => 1),
    array('id' => 3, 'name' => 'さんま', 'price' => 180, 'category' => 2),
    array('id' => 4, 'name' => 'マグロ', 'price' => 300, 'category' => 2),
);

$results = Ginq::from($items)  // 元になる配列
    ->join(
        $categories,            // 結合する配列
        '[category]',           // 元になる配列側の結合フィールド
        '[id]',                 // 結合する配列側の結合フィールド
        function($item, $category, $itemKey, $categoryKey) {
            // 元になる配列にあった行が $item、結合する配列にあった行が $category として渡される
            // 結合後の1行ごとにここが呼ばれるので、結合結果として採用する行(1行分)を返す(SELECTにあたる)
            return array('id' => $item['id'], 'name' => $item['name'], 'price' => $item['price'], 'category_name' => $category['name']);
        }
    );
?>
<table>
<?php foreach ($results as $result): ?>
<tr>
    <td><?php echo $result['id'] ?></td>
    <td><?php echo $result['name'] ?></td>
    <td><?php echo $result['price'] ?></td>
    <td><?php echo $result['category_name'] ?></td>
</tr>
<?php endforeach; ?>
</table>
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