8ビットの並びを逆転して遊ぶ その1

いろいろ、注意

• UNOでの予定は、未定

プログラム

#include <iostream>
using namespace std;
int main(void){
    // Your code here!
    
    long a;
    
    a = 0b11110000;
    //a = 0b10000000;
    //a = 0b01000000;
    //a = 0b00100000;
    //a = 0b00010000;
    //a = 0b00001000;
    //a = 0b00000100;
    //a = 0b00000010;
    //a = 0b00000001;

    //printf("1[%x]\n",a);
    a = a | (a << 8);
    //printf("2[%x]\n",a);
    a = (a & 0b000110011000000 ) | ( (a << 4) & 0b011001100000000 );
    //printf("3[%x]\n",a);
    a = (a & 0b010101010000000 ) | ( (a << 2) & 0b101010100000000 );
    a = a >> 7;
    printf("[%02x]\n",a);

}

[0f]

おまけ

1234567890123456789012345
                 44332211
         44332211    <<8
        0b000111111110000      
             22114433 
        0b000110011000000       
         22114433    <<4
        0b011001100000000 
           11223344      
           badcfehg      
        0b010101010000000
         badcfehg    <<2 
        0b101010100000000
          abcdefgh      *
                 abcdefgh  >>7