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UNICORNプログラミングコンテスト2021(AtCoder Beginner Contest 225) 参戦記

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UNICORNプログラミングコンテスト2021(AtCoder Beginner Contest 225) 参戦記

ABC225A - Distinct Strings

2分半で突破. 最大で6種類しかないので、サクッと生成してしまうのが良いですね.

S = input()

t = set()
t.add(S[0] + S[1] + S[2])
t.add(S[0] + S[2] + S[1])
t.add(S[1] + S[0] + S[2])
t.add(S[1] + S[2] + S[0])
t.add(S[2] + S[0] + S[1])
t.add(S[2] + S[1] + S[0])
print(len(t))

ABC225B - Star or Not

4分で突破. 全てのiについてaibiのどちらかに特定の数字が入っているかどうかですね.

from sys import setrecursionlimit, stdin

readline = stdin.readline
setrecursionlimit(10 ** 6)

N = int(readline())
ab = [list(map(int, readline().split())) for _ in range(N - 1)]

x = ab[0][0]
if all(x in l for l in ab):
    print('Yes')
    exit()
x = ab[0][1]
if all(x in l for l in ab):
    print('Yes')
    exit()
print('No')

ABC225C - Calendar Validator

12分半で突破、WA1. 7の倍数は右端でしか出ないことをチェックし漏れていましたね…….

from sys import setrecursionlimit, stdin

readline = stdin.readline
setrecursionlimit(10 ** 6)

N, M = map(int, readline().split())
B = [list(map(int, readline().split())) for _ in range(N)]

x = B[0][0]
for i in range(N):
    if (B[i][0] - 1) // 7 != (B[i][M - 1] - 1) // 7:
            print('No')
            exit()
    for j in range(M):
        if x + 7 * i + j != B[i][j]:
            print('No')
            exit()
print('Yes')

ABC225D - Play Train

36分半で突破. Doubly linked list で管理するだけみたいな簡単な問題じゃないよなあと思いつつ、計算量を見積もったらそれだけの簡単な問題でアレってなった.

from sys import stdin

readline = stdin.readline

N, Q = map(int, readline().split())

front = [0] * (N + 1)
rear = [0] * (N + 1)
result = []
for _ in range(Q):
    s = readline()
    if s[0] == '1':
        _, x, y = map(int, s.split())
        rear[x] = y
        front[y] = x
    elif s[0] == '2':
        _, x, y = map(int, s.split())
        rear[x] = 0
        front[y] = 0
    elif s[0] == '3':
        _, x = map(int, s.split())
        while front[x] != 0:
            x = front[x]
        t = []
        while True:
            t.append(x)
            if rear[x] == 0:
                break
            x = rear[x]
        result.append(' '.join(str(x) for x in [len(t)] + t))
print(*result, sep='\n')
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