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Python で ntp server から時刻を取得する (Python 3 版)

Last updated at Posted at 2019-04-28

Python で ntp server から時刻を取得する (Python 3 版)

Python で ntp server から時刻を取得する (Python 2 版) を Python 3 に移植した.
2to3 を使ってみたら、2208988800L の最後の L を取れって言われたので、それを修正して実行してみたら

TypeError: a bytes-like object is required, not 'str'

って怒られた. しょんぼり.

テスト

>>> ntp_now('ntp.jst.mfeed.ad.jp')
datetime.datetime(2019, 4, 29, 0, 3, 30)

コード

def ntp_now(server, port = 123):
    from socket import socket, AF_INET, SOCK_DGRAM
    from struct import unpack
    from datetime import datetime
    with socket(AF_INET, SOCK_DGRAM) as s:
        s.sendto(b'\x1b' + 47 * b'\0', (server, port))
        result = s.recvfrom(1024)[0]
    if result:
        return datetime.fromtimestamp(unpack(b'!12I', result)[10] - 2208988800)
    else:
        None

b を付けまくって、finally close を with 文で差し替えた. with がデフォルトで使えるのは 2.6 からだから 2.5 時代に書いたのかなあ.

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