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文字列の二次元配列をポインタのポインタに変換する方法

Last updated at Posted at 2023-06-22

C言語で文字列の二次元配列をポインタのポインタに変換する方法です。

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define ARRAY_SIZE 3
#define LEN 10

int main(void){
    char str_array[ARRAY_SIZE][LEN] = {
        "neko",
        "inu",
        "usagi"
    };

    char** str_pp = NULL;

    str_pp = (char**)malloc(sizeof(char*) * ARRAY_SIZE);
    if(str_pp == NULL){
        return EXIT_FAILURE;
    }

    for(int i = 0; i< ARRAY_SIZE; i++){
        str_pp[i] = (char*)malloc(sizeof(char) * LEN);
        if(str_pp[i] == NULL){
            return EXIT_FAILURE;
        }
        strncpy(str_pp[i], str_array[i], LEN);
    }

    for(int i = 0; i< ARRAY_SIZE; i++){
        fprintf(stdout, "%s\n", str_pp[i]);
    }

    for(int i=0; i<ARRAY_SIZE;i++){
        free(str_pp[i]);
    }

    free(str_pp);

    return EXIT_SUCCESS;
}
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