$a > 0 $ は、題意。
$a = 1$ であれば、$a^{\frac{1}{n}} = 1$
(1) まず、$a > 1$の場合を考える。
$n_0 \geq\ a$ なる $n_0 \in {\bf N}$ は、必ず存在し、$n \geq n_0$ かつ$n > 2$ ならば、
$1^{\frac{1}{n}} < a^{\frac{1}{n}} \leq n^{\frac{1}{n}}$
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