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Atcoder B - Palace

Last updated at Posted at 2022-05-05

問題

回答

N = int(input())
T,A = map(int,input().split())
H = [int(i) for i in input().split()]

ans = 1
dis = 0
list = []

for i in range(N): #それぞれの地点からの差分を計算する。
  dis = abs(T - H[i] * 0.006- A) 
  list.append(dis) #配列に格納。
  ans = list.index(min(list))+1 #配列の中で一番小さいindexに、1を足したものが答え。一番小さい値の順番に1を足した数が答えとなっている。

print(ans)

ポイント

個人的にはans = list.index(min(list))+1の部分。

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