実行スクリプト名は__file__で取得できる.
これとos.pathモジュールを組み合わせて,実行スクリプトから相対パスでファイルにアクセスする.
base = os.path.dirname(os.path.abspath(__file__))
name = os.path.normpath(os.path.join(base, '../local/local_db'))
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