tool-taro posted at Feb 06, 2016

Java 正規表現を使ってUser-Agentから端末型番を簡単に取得する(ガラケー編)

{ "DoCoMo/2.0 F900i(c100;TB;W22H12)", "UP.Browser/3.04-SN12 UP.Link/3.4.4", "KDDI-HI31 ...

lampt posted at Mar 18, 2019

よく使用される正規表現

[0-9]*)*/ 文字と数字空白なし：/^[a-zA-Z0-9]*$/ 空白有り：/^[a-zA-Z0-9 ]*$/ Email Email：/^([a-

cr_tk posted at Jan 12, 2018

・連続ドット入力可能 [0-9a-zA-Z.\-_]*(?! .@([0-9a-zA-Z])+.[0-9a-zA-Z.\-]+$ 入力値 ...

emesh posted at Feb 24, 2020

; //正規表現でメモを分割する preg_match_all('/[一-龠]+|[ぁ-ん]+|[ァ-ヴー]+|[a-zA-Z0-9]+|[ａ-ｚＡ-Ｚ０-９]+/u', $ ...

HaraShun posted at Nov 20, 2018

v=_PO7a31J4Go ）書籍「Web制作者のためのGitHubの教科書チームの効率を最大化する共同開発ツール Web制作者のための教科書シリーズ」（https: ...

blackenedgold posted at Dec 22, 2015

ブログから改善率の高い正規表現を抜き出すと、 a[^x]{20}b (31%) [a-zA-Z]+ing (49%) [a-zA-Z]+i ...

ponsuke0531 posted at Dec 11, 2018

a-zA-Z]+[a-zA-Z0-9-]*[a-zA-Z0-9](?:\.[a-zA-Z]+[a-zA ...

ishishow posted at Dec 26, 2020

(Pythonは弱弱だが経験あり) 31問目（問題125) 125. import ( "regexp" "strings" ) func isPalindrome(s st ...

hawk777 posted at Mar 12, 2020

なソート list1 = ["A1","A2","A3","A10","A11","A12","A13","A20","A21","A22","A23","A30","A31 ...

agotoh posted at Dec 13, 2017

ed_port", guest: 80, host: 8080 config.vm.network "private_network", ip: "192.168.33.31 ...

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